Optimal. Leaf size=363 \[ -\frac {2 a^{7/4} e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (7 \sqrt {a} B+5 A \sqrt {c}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}+\frac {4 a^{9/4} B e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{15 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {4 a^2 B e^2 x \sqrt {a+c x^2}}{15 c^{3/2} \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}-\frac {2 a e \sqrt {e x} \sqrt {a+c x^2} (5 A+7 B x)}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c} \]
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Rubi [A] time = 0.42, antiderivative size = 363, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {833, 815, 842, 840, 1198, 220, 1196} \[ -\frac {2 a^{7/4} e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} \left (7 \sqrt {a} B+5 A \sqrt {c}\right ) F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {4 a^2 B e^2 x \sqrt {a+c x^2}}{15 c^{3/2} \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}+\frac {4 a^{9/4} B e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{15 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {2 a e \sqrt {e x} \sqrt {a+c x^2} (5 A+7 B x)}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c} \]
Antiderivative was successfully verified.
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Rule 220
Rule 815
Rule 833
Rule 840
Rule 842
Rule 1196
Rule 1198
Rubi steps
\begin {align*} \int (e x)^{3/2} (A+B x) \sqrt {a+c x^2} \, dx &=\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {2 \int \sqrt {e x} \left (-\frac {3}{2} a B e+\frac {9}{2} A c e x\right ) \sqrt {a+c x^2} \, dx}{9 c}\\ &=\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {4 \int \frac {\left (-\frac {9}{4} a A c e^2-\frac {21}{4} a B c e^2 x\right ) \sqrt {a+c x^2}}{\sqrt {e x}} \, dx}{63 c^2}\\ &=-\frac {2 a e \sqrt {e x} (5 A+7 B x) \sqrt {a+c x^2}}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {16 \int \frac {-\frac {45}{8} a^2 A c^2 e^4-\frac {63}{8} a^2 B c^2 e^4 x}{\sqrt {e x} \sqrt {a+c x^2}} \, dx}{945 c^3 e^2}\\ &=-\frac {2 a e \sqrt {e x} (5 A+7 B x) \sqrt {a+c x^2}}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {\left (16 \sqrt {x}\right ) \int \frac {-\frac {45}{8} a^2 A c^2 e^4-\frac {63}{8} a^2 B c^2 e^4 x}{\sqrt {x} \sqrt {a+c x^2}} \, dx}{945 c^3 e^2 \sqrt {e x}}\\ &=-\frac {2 a e \sqrt {e x} (5 A+7 B x) \sqrt {a+c x^2}}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {\left (32 \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {-\frac {45}{8} a^2 A c^2 e^4-\frac {63}{8} a^2 B c^2 e^4 x^2}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{945 c^3 e^2 \sqrt {e x}}\\ &=-\frac {2 a e \sqrt {e x} (5 A+7 B x) \sqrt {a+c x^2}}{105 c}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {\left (4 a^{5/2} B e^2 \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {1-\frac {\sqrt {c} x^2}{\sqrt {a}}}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{15 c^{3/2} \sqrt {e x}}-\frac {\left (4 a^2 \left (7 \sqrt {a} B+5 A \sqrt {c}\right ) e^2 \sqrt {x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {a+c x^4}} \, dx,x,\sqrt {x}\right )}{105 c^{3/2} \sqrt {e x}}\\ &=-\frac {2 a e \sqrt {e x} (5 A+7 B x) \sqrt {a+c x^2}}{105 c}-\frac {4 a^2 B e^2 x \sqrt {a+c x^2}}{15 c^{3/2} \sqrt {e x} \left (\sqrt {a}+\sqrt {c} x\right )}+\frac {2 A e \sqrt {e x} \left (a+c x^2\right )^{3/2}}{7 c}+\frac {2 B (e x)^{3/2} \left (a+c x^2\right )^{3/2}}{9 c}+\frac {4 a^{9/4} B e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{15 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}-\frac {2 a^{7/4} \left (7 \sqrt {a} B+5 A \sqrt {c}\right ) e^2 \sqrt {x} \left (\sqrt {a}+\sqrt {c} x\right ) \sqrt {\frac {a+c x^2}{\left (\sqrt {a}+\sqrt {c} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{c} \sqrt {x}}{\sqrt [4]{a}}\right )|\frac {1}{2}\right )}{105 c^{7/4} \sqrt {e x} \sqrt {a+c x^2}}\\ \end {align*}
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Mathematica [C] time = 0.09, size = 118, normalized size = 0.33 \[ \frac {2 e \sqrt {e x} \sqrt {a+c x^2} \left (\sqrt {\frac {c x^2}{a}+1} \left (a+c x^2\right ) (9 A+7 B x)-9 a A \, _2F_1\left (-\frac {1}{2},\frac {1}{4};\frac {5}{4};-\frac {c x^2}{a}\right )-7 a B x \, _2F_1\left (-\frac {1}{2},\frac {3}{4};\frac {7}{4};-\frac {c x^2}{a}\right )\right )}{63 c \sqrt {\frac {c x^2}{a}+1}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.80, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (B e x^{2} + A e x\right )} \sqrt {c x^{2} + a} \sqrt {e x}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c x^{2} + a} {\left (B x + A\right )} \left (e x\right )^{\frac {3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.11, size = 342, normalized size = 0.94 \[ -\frac {2 \sqrt {e x}\, \left (-35 B \,c^{3} x^{6}-45 A \,c^{3} x^{5}-49 B a \,c^{2} x^{4}-75 A a \,c^{2} x^{3}-14 B \,a^{2} c \,x^{2}-30 A \,a^{2} c x +42 \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, B \,a^{3} \EllipticE \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )-21 \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, B \,a^{3} \EllipticF \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )+15 \sqrt {2}\, \sqrt {\frac {-c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-\frac {c x}{\sqrt {-a c}}}\, \sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}\, \sqrt {-a c}\, A \,a^{2} \EllipticF \left (\sqrt {\frac {c x +\sqrt {-a c}}{\sqrt {-a c}}}, \frac {\sqrt {2}}{2}\right )\right ) e}{315 \sqrt {c \,x^{2}+a}\, c^{2} x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {c x^{2} + a} {\left (B x + A\right )} \left (e x\right )^{\frac {3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\left (e\,x\right )}^{3/2}\,\sqrt {c\,x^2+a}\,\left (A+B\,x\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [C] time = 8.75, size = 97, normalized size = 0.27 \[ \frac {A \sqrt {a} e^{\frac {3}{2}} x^{\frac {5}{2}} \Gamma \left (\frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{4} \\ \frac {9}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 \Gamma \left (\frac {9}{4}\right )} + \frac {B \sqrt {a} e^{\frac {3}{2}} x^{\frac {7}{2}} \Gamma \left (\frac {7}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {7}{4} \\ \frac {11}{4} \end {matrix}\middle | {\frac {c x^{2} e^{i \pi }}{a}} \right )}}{2 \Gamma \left (\frac {11}{4}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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